4a^2+8a=2a

Solution for 4a^2+8a=2a equation:

4a^2+8a=2a

We move all terms to the left:

4a^2+8a-(2a)=0

We add all the numbers together, and all the variables

4a^2+6a=0

a = 4; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·4·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*4}=\frac{-12}{8}
=-1+1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*4}=\frac{0}{8}
=0
$